Question
Archers 'A' and 'B' take aim at a target. if the
probability of 'A' hitting the target is 90% and of 'B' missing the target is 90% what is the probablity that both 'A' and 'B' miss the target?Solution
ATQ, Probability of Archer 'A' hitting the target is 90% = 9/10 ⇒ Probability of Archer 'A' missing the target is 10% = 1/10 Probability of Archer 'B' missing the target is 90% = 9/10 ⇒ Probability of Archer 'B' hitting the target is 10% = 1/10 ∴ Probability that A and B will miss the target = 1/10 × 9/10 = 9%
What will be the output of the code
int main(){
int x= 10;
int y=10;
int s=-(-x-y)
cout<
return 0;
}
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