Question
The product of the two numbers is 1500 and their HCF is
10. The number of such possible pairs is/are:Solution
Let two numbers be 10x and 10y where, x and y are two co-prime to each other According to the question, we have Product of two numbers = 1500 ⇒ (10x) × (10y) = 1500 ⇒ xy = 1500/100 ⇒ xy = 15 No. of possible pairs which are co-prime to each other is ⇒ (15 × 1), (5 × 3) ∴ The number of possible pairs is 2.
3960, 660, 720, 122, 180, 30
2400,3600,5400,7200,12150
210, 140, 105, 84, 70, 63, 52.5
112, 236, 374, 546, 790, 1376
88, 112, 78, 120, 64, 136
Find the wrong number in the series.
3, 6, 18, 72, 360, 2160, 151202824 2314 1973 1759 1634 1574
120, 136, 111, 147, 93, 162, 81
Find the wrong number in given number series.
1116, 1135, 1158, 1187, 1224, 1278.
Find the wrong number in given number series.
2658, 2654, 2681, 2645, 2999, 2918
