Question
The lengths of one side and a diagonal of a rectangle
are 63 cm and 65 cm, respectively. What is the perimeter (in cm) of a square whose area is one-seventh of that of the rectangle?Solution
According to the question 652 = (breadth)2 + 632 β 4225 = (breadth)2 + 3969 β (breadth)2 = 4225 β 3969 β breadth = β256 β Length = 16 So, area = 63 Γ 16 Area of the square = 63 Γ 16/7 β 144 = a2 So, a = 12 Perimeter = 4 Γ 12 = 48 cm β΄ The perimeter (in cm) of a square is 48
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