Question
The lengths of one side and a diagonal of a rectangle
are 63 cm and 65 cm, respectively. What is the perimeter (in cm) of a square whose area is one-seventh of that of the rectangle?Solution
According to the question 652 = (breadth)2 + 632 ⇒ 4225 = (breadth)2 + 3969 ⇒ (breadth)2 = 4225 – 3969 ⇒ breadth = √256 ⇒ Length = 16 So, area = 63 × 16 Area of the square = 63 × 16/7 ⇒ 144 = a2 So, a = 12 Perimeter = 4 × 12 = 48 cm ∴ The perimeter (in cm) of a square is 48
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