Question
Pipe A can fill a tank in 30 hours. Pipes A and B together can fill it in 12 hours. Pipes B and C together can fill it in 15 hours. In how many hours will A, B and C together fill the tank?
Solution
ATQ, A = 1/30 B = 1/12 − 1/30 B = (5 − 2)/60 = 3/60 = 1/20 B + C = 1/15 C = 1/15 − 1/20 C = (4 − 3)/60 = 1/60 A + B + C = 1/30 + 1/20 + 1/60 = (2 + 3 + 1)/60 = 6/60 Required time = 60/6 hours = 10 hours
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