📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    âš¡ Month End Offer - Flat 52% Off On All Courses! Enroll Now âš¡
    00:00:00 AM Left

    Question

    Pipe ‘A’ fills a tank in 36 hours and pipe ‘B’

    empties it in 90 hours. If both are opened simultaneously, how much time will it take to fill 60% of the tank?
    A 42 hours Correct Answer Incorrect Answer
    B 40 hours Correct Answer Incorrect Answer
    C 36 hours Correct Answer Incorrect Answer
    D 45 hours Correct Answer Incorrect Answer

    Solution

    Let the capacity of the tank be 180 litres. So, efficiency of pipe ‘A’ = 180 ÷ A = 5 litres/hour And efficiency of pipe ‘B’ = 180 ÷ B = 2 litres/hour So, combined efficiency of both pipes = 5 – 2 = 3 litres/hour So, time taken to fill 60% of the tank = (180 × 0.60) ÷ 3 = 108 ÷ 3 = 36 hours

    Practice Next
    More Pipes and cisterns Questions

    Relevant for Exams:

    ask-question