Question
Pipe ‘A’ takes 50 hours to fill a tank. Pipe
‘B’ takes 100 hours to empty the same tank. If they are opened together, how long will it take to fill 80% of the tank?Solution
Let the capacity of the tank be 200 litres. So, efficiency of pipe ‘A’ = 200 ÷ A = 4 litres/hour And efficiency of pipe ‘B’ = 200 ÷ B = 2 litres/hour So, combined efficiency of both pipes = 4 – 2 = 2 litres/hour So, time taken to fill 80% of the tank = (200 × 0.80) ÷ 2 = 160 ÷ 2 = 80 hours
More Pipes and cisterns Questions
- Simplify the expression:
30% of [140% of (50 + 30) + 110] ÷ 70 × 100 24% of 15% of 500 + 122 = ?2 – (232 ÷ 2)
If (3 × 144 – 252 ÷ 14) ÷ 18 = √1024 – x, then find the value of ‘x’.
- What will come in place of (?), in the given expression.
144 ÷ √36 + 13² – 100 = ? {(80% of 650 + 25 × 12) – 20 × ?} = 760
31% of 1900 - ? = 73
Simplify the following expression.
(3-3 × 3 + 3 ÷ 3 + 3 × 5) × 2 of 5 + (2 + 2 ÷ 2 + 2 × 2 - 2)
Find the value of ‘x’ if (5 × 196 – 340 ÷ 17) ÷ 20 = √1600 – x.
The value of 42 ÷ 9 of 6 - [64 ÷ 48 x 3 – 15 ÷ 8 x (11 – 17) ÷ 9] ÷ 14 is:
√529 + √64 + 92 = ?
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