Question
Pipe A alone fills a tank in 18 hours. Pipes A and B
together fill it in 12 hours. Pipes B and C together fill it in 9 hours. Find the time taken by A, B and C together to fill the tank.Solution
ATQ, A = 1/18 A + B = 1/12 So, B = 1/12 − 1/18 B = (3 − 2)/36 = 1/36 B + C = 1/9 So, C = 1/9 − 1/36 C = (4 − 1)/36 = 3/36 = 1/12 A + B + C = 1/18 + 1/36 + 1/12 = (2 + 1 + 3)/36 = 6/36 = 1/6 Required time = 6 hours
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