Question
Pipes P and Q can fill a tank in 12 hours and 15 hours
respectively, while a third pipe C can empty the tank in 24 hours. If all three pipes are opened simultaneously at 4:00 a.m., at what time will the tank be 65% full?Solution
Let the capacity of the tank be 120 units
Efficiency of pipe ‘A’ = 120/12 = 10 units/hour
Efficiency of pipe ‘B’ = 120/15 = 8 units/hour
Efficiency of pipe ‘C’ = 120/24 = 5 units/hour
Tank filled in 1 hour = 10 + 8 – 5 = 13 units
Time taken to fill 65% of the tank = 0.65 × 120/13 = 6 hours
Therefore, tank will get filled at (4 + 6) = 10 a.m.
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