Question
Pipes P and Q can fill a tank in 12 hours and 15 hours
respectively, while a third pipe C can empty the tank in 24 hours. If all three pipes are opened simultaneously at 4:00 a.m., at what time will the tank be 65% full?Solution
Let the capacity of the tank be 120 units
Efficiency of pipe ‘A’ = 120/12 = 10 units/hour
Efficiency of pipe ‘B’ = 120/15 = 8 units/hour
Efficiency of pipe ‘C’ = 120/24 = 5 units/hour
Tank filled in 1 hour = 10 + 8 – 5 = 13 units
Time taken to fill 65% of the tank = 0.65 × 120/13 = 6 hours
Therefore, tank will get filled at (4 + 6) = 10 a.m.
√1764 + 35 × 8 + 39 = ?2
18% of 200 - 16% of 150 = ?
25% of 30% of 3/5 of 14500 =?
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
7/3 of 4/5 of 15/56 of ? = 83
What will come in place of the question mark (?) in the following expression?
40% of 150 – ?% of 80 = 25% of 400
555.05 + 55.50 + 5.55 + 5 +0.55 = ?
64.5% of 800 + 36.4% of 1500 = (?)² + 38
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 × 4) = ?2
Simplify the following expression:
((32)4 - 1)/33×31× (210+1)
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