Pipe P can fill half of the tank in 8 hrs 5 min and pipe

Solution

Pipe A can fill half of the tank in =8 hrs 5 min Then pipe A can fill the full tank in =16 hrs 10 min So, pipe A can fill the full tank approximately in =16 hrs Pipe B can fill the same tank approximately in =16 hrs Pipe C can empty the full tank in =12 hrs One hour capacity of A = 1/16 One hour capacity of B = 1/16 One hour capacity of C = -1/12 Total capacity = 48 units (LCM of 16, 16, 12) Efficiency of pipe A = 3 units/hr Efficiency of pipe A = 3 units/hr Efficiency of pipe A = -4 units/hr = 16 hrs