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Let the total capacity of tank be 120 units Efficiency of pipe ‘A’ = 120/30 = 4 units/hour Efficiency of pipe ‘B’ = 120/40 = 3 units/hour Tank filled in 2 hours = (4 – 3) = 1 units Therefore, tank filled in (2 × 30 = 60 hours) = 1 × 30 = 30 units Required percentage of tank filled = (30/120) × 100 = 25%
1.25 × 36 + 2.75 × 40 = ? × 3.1
{(420 ÷ 28)% of 1400} ÷ 7 = ?
(0.1 × 0.2 × 0.3) + (0.3 × 0.4 × 0.5) =?
280 ÷ 14 + 11 × 12 – 15 × 6 = ?
8(3/4) + 5(1/6) – 4(3/4) = ?
567-4824 ÷ 134 =? × 9
150% of ? + 280 ÷ 35 = 132 - 122 + 7
(7/4×18/21)+ (51/7× 28/17) + (25/2 × 48/10) =?
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18