Question
A cistern has two pipes one can fill it with water in 16
hours and other can empty it in 10 hours. In how many hours will the cistern be emptied if both the pipes are opened together when 3/5th of the cistern is already filled with water?Solution
If both pipes are open, then total units per hour empty the tank (A-B) = 5-8 = -3 units According to question, Tank has 3/5 of its total capacity in the beginning 3/5 × 80= 48 units Time taken to empty the tank = 48/(-3) = 16 hours.
6000 3002 1503 ? 378.75 191.375 97.6875
...1, 27, ?, 343, 729, 1331
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
51 53 109 332 ? 6686
...9 4.5 4.5 9 36 ?
5 16 ? 66 119 200
...1 1 8 4 27 9 ?
...What will be the next number in the series?
2, 7, 23, 70, ?
There are three series given below which are following with the same pattern.
Series I: 1, 12, 38, 193, 1355
Series II: 6, B, C, D, E
...Direction: Which of the following will replace ‘?’ in the given question?
5, 18, ‘?’, 126, 296, 586, 1044
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