Question
A student has to obtain 35% of the total marks to pass.
He got 214 marks and failed by 31 marks. What are the maximum marks?Solution
Given that the student got 214 marks and still he failed by 31 marks => The minimum pass mark = 214 + 31 = 245 Minimum pass mark %= 35% of the total mark So, 35% of the total mark = 245 => Total mark = 24500/35= 700
?% of 1499.89 + 54.14 × 8 = 25.05% of 5568.08
? = 41.92% of (34.92 x 40.42) + 29.78% of 399.84
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
? + 163.99 – 108.01 = 25.01 × 6.98
80.09 * √144.05+ ? * √224.87 = (2109.09 ÷ √1368.79) * 19.89
(15.15 ×  31.98) + 30.15% of 719.99 = ? + 124.34
(124.99)² = ?
6.992 + (2.01 × 2.98) + ? = 175.03
(627.98 ÷ 3.98 + 11.01 X 12.98 - ?) ÷ √623 = (178.98 + 37.08) ÷ 23.98Â