Question
In a test series, Ishaan scored 50 marks less than
Kirti. Kirti scored 34 more marks than Lata. Mohit scored 120 marks which is 40 marks more than Ishaan. Naina’s score is 27 less than the maximum marks of the test. Ojas, who scored 19 marks less than Lata in the first test which was of 160 marks, has to get an average score of at least 80% in two tests. If the second test carrying 190 marks, what percentage of marks should he score in the second test to get the overall average score?(Calculate approximate value)Solution
ATQ, Ishaan’s score = Mohit's score - 40 = 120 - 40 = 80 Kirti’s score = Ishaan's score + 50 = 80 + 50 = 130 Lata’s score = Kirti's score - 34 = 130 - 34 = 96 Ojas’s score in the first test = Lata's score - 19 = 96 - 19 = 77 Total maximum marks of tests = 160 + 190 = 350 Ojas has to score 80% of 350 = 350 × (80/100) = 280 marks Remaining required marks = 280 - 77 = 203 Required % = (203/190) × 100 = 106.8421% or 106%
What will be the output of the code
int main(){
int x= 10;
int y=10;
int s=-(-x-y)
cout<
return 0;
}
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