Question
The price of a laptop undergoes two consecutive changes
over two months. In the first month, its price decreases by 10%, followed by an increase of 20% in the second month. After these adjustments, the laptop’s price at the end of the second month is ₹39,960. Determine the original price of the laptop before any changes were applied.Solution
Let the original price of laptop was = 100x Price of laptop after 1 month = 90% of 100x = 90x Price of laptop after secondmonth = 120% of 90x = 108x 108x = 39,960 x = 370 original price of laptop = 100x = 37,000
? = 340.24 + 1001.97 – 6.992 Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
[54.96 × √99.96 – {(25.02/6.84)% of 280.24}]/(3.032 × 19.87) = ?
41.97 × 5.12 ÷ 2.99 + 49.89 = ?× 1.99
3374.89% of 31.80 – 1739.85% of 44.72 = (?2 )% of 1188.13Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value....
99.99% of 9.99 + 299.98% of 129.98 = ?2Â
7/12 of 539.98 – 23.98 × 9.03 + 77.89 = ?