Question
If the length of a rectangle is increased by 60%, what
would be the percentage decrease (correct to the nearest integer) in the width to maintain the same area?Solution
Let the length and width of the rectangle =100 Area =100×100=10000. Length after 60% increase length =160 And let the x% decrease in width =(100-x) Area =(100-x) ×160. ATQ- (100-x) ×160 =10000 16x =600 X=37%(approx.) Required Answer=100-37 =63%
More Percentage Questions
(12% of 1250 + 85% of 400) x 10 = ?2
1/6+ 999*53/54 ×9 = ?
(49 x ?) / 3.5 + 389 = 627
What value should come in place of the question mark (?) in the following question?
20% of 1500 – 75% of 200 = 125% of ?
Solve the following:
1500 ÷ (9 × 18 ÷ 6 × 3 – 45) ²
- Which of the following expressions are equal?
'A' = 81 ÷ 9 × 6 - 27
'B' = (3/2) × (40/3) + 30 ÷ 6
'C' = (40 + 12 - 22) ÷ 6 × 5 Find the simplified value of the given expression
1111.25 × 9.05 + 2323.23 × 9.05 – 2121.37 ×9.05 =?
Find the value of x.
 √441 ÷ 21+ √400 = 1 × x
- Determine the value of ‘p’ if p% of 600 + {1440 ÷ p of 16} × 8 = 156
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