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    Question

    If the length of a rectangle is increased by 60%, what

    would be the percentage decrease (correct to the nearest integer) in the width to maintain the same area?
    A 59% Correct Answer Incorrect Answer
    B 63% Correct Answer Incorrect Answer
    C 60% Correct Answer Incorrect Answer
    D 58% Correct Answer Incorrect Answer

    Solution

    Let the length and width of the rectangle =100 Area =100×100=10000. Length after 60% increase length =160 And let the x% decrease in width =(100-x) Area =(100-x) ×160. ATQ- (100-x) ×160 =10000 16x =600 X=37%(approx.) Required Answer=100-37 =63%

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