Question
A number is first increased by 50% and then decreased by
50%. If the net change in the number is 400, then find the original number.Solution
ATQ, Let the original number be '100a'. Final number = 100a x (150/100) x (50/100) = '75a' Net decrease = 100a - 75a = '25a' Or, 25a = 400 Or, 'a' = 400 / 25 = 16 Therefore, required number = 100a = 16 x 100 = 1600
Quantity I: A vessel contains a mixture of milk and water in the ratio of 7 : 5. If 9 litre of mixture is sold and replaced by same amount of water then...
I. 2x² + 15 x - 27 = 0
II. 3 y² + 25 y - 18 = 0
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 32x + 207 = 0
Equation 2: y² - 51y + 648 = 0
I. x2 + (9x/2) + (7/2) = - (3/2)
II. y2 + 16y + 63 = 0
I.70x² - 143x + 72 = 0
II. 80 y² - 142y + 63 = 0
I. x2 – 13x + 40 = 0
II. 2y2 – 15y + 13 = 0Â
I. 7x² + 27x + 18 = 0
II. 19y² - 27y + 8 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
l. x2 - 16x + 64 = 0
II. y2Â = 64
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