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For statement first – X =12, y=-2 and z= -10 x+ y+ z =12 -2-10=0 x +y + z=0 so. x³ + y³+ z³ = 3xyz = 3 ×12 × -2× -10 = 720 For statement second – x + y = 48, 4xy = 124 4x² +4y² = 4480 4(x² +y²) = 4480 4(x² +y²) = 4[ (x+ y) ²-2xy] =4[(48) ² -2×31] =4[2404-62] =4 ×2342=9368,
The substance DDT is now
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