Question

If x, y and z are real numbers such that (x-3)2+(y-6)2+(z-8)2= 0 then (x+y+z) is equal to

A 19 Correct Answer Incorrect Answer
B 17 Correct Answer Incorrect Answer
C 14 Correct Answer Incorrect Answer
D 13 Correct Answer Incorrect Answer

Solution

if a2+b2+c2 +...so on = 0 then a=b=c=....so on = 0 So ATQ, x-3=0, y-6=0 and z-8=0 So x=3, y =6 and z= 8 hence x+y+z =3+6+8 =17 ` `

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