(123×123×123 + 130×130×130)/(123×123 - 123×130 + 130×130) = ?
let a = 123, b = 130 so (123×123×123+130×130×130)/(123×123-123×130+130×130) = (a3 + b3)/(a2 - ab + b2) => ((a+b) x (a2+ b2- ab))/( a 2+ b 2- ab ) = (a+b) => 123 + 130 = 253 ` ` ` `
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