Question
A and B together have total of Rs.5600 out of which they
donated 10% to the orphanage school. The remaining amount is to be then redistributed between them in such a manner that A gets 40% more amount than B. If the amount received by A is Rs.3X, then find the value of [(X/7) + 14].Solution
Let the amount received by B be Rs.P. Therefore, amount received by A = 1.40 x P = Rs.1.4P According to the question, => (P + 1.4P) = 5600 x 0.90 => 2.4P = 5040 => P = 2100 Share of A = 5040 – 2100 = Rs.2940 So, 3X = 2940 => X = 980 Required value = [(X/7) + 14] = 140 + 14 = 154
- What will come in the place of question mark (?) in the given expression?
(198/13) X (52/11) - ? ÷ 5 = 13 + 68 ÷ 4 What will come in the place of question mark (?) in the given expression?
√4096 + √3249 = (?)2
Simplify the following expressions and choose the correct option.
(96 ÷ 8 + 72 ÷ 9) * 3
((12+12+12+12)÷4)/((8+8+8+8+8+8)÷16) = ?
{(5/8) + (4/5)} × (?/19) = 33
(72 × 52 + 1555 )/(79+60) = 2000 ÷ ?
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 × 4) = ?2
- What will come in place of (?) in the given expression.
(14)² – (12)² = ? What value should come in the place of (?) in the following questions?
√(60 + 82 + 101) * 5 = ?
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