Question
Two numbers are less than a third number by 44% and 51%
respectively. Find the percent by which the second number is less than the first.Solution
Let the third number be 100. Then, first number will be = 100 – 44 = 56 And the second number will be = 100 – 51 = 49 Required % = [(56 – 49)/56] × 100 = 12.5%
14.99% of 7820 + 5535.25 ÷ 123.001 - ? = 84
18.22 × 11.99 + 154.15 = ?
 (3/5) of 3025 + (18² + 12²) = ? + 22.22% of 1125
5.25 x 4.09 + 3.99 x 9.67 + 6.01 x 14.88 = ?
? = 16.08 + 13.99 × 25.07
20.99 × √4.09 × 30.09 = ? × √195.99 × 15.09
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
30.01 × √1023 + 196 = ? 2 – 287
?% of (150.31 ÷ 14.97 × 50.011) = 319.98