Question
The sum of the monthly incomes of βAβ, βBβ and
βCβ is Rs. 50000 which is 4 times the monthly income of βCβ. If βAβ spends 55% of his income while βBβ spends 80% of his income and the sum of their savings is Rs. 15000, then find the savings of βAβ.Solution
Monthly income of βCβ = 50000/4 = Rs. 12500 Let the monthly income of βAβ be Rs. x Therefore, monthly income of βBβ = Rs. (37500 β x) According to the question, 0.45x + 0.20(37500 β x) = 15000 Or, 0.25x = 7500 Or, savings of βAβ = 0.45x = Rs. 13500
390/? = √256 + 3.5
?/343 = 7/?
7(1/7)% of 3500 + 6(2/3)Β % of 6000 = ? + 552.5
690 Γ· (75% of 460) = ? Γ· (50% of 160)
(75 + 0.25 Γ 10) Γ 4 = ?2 - 14

263 + 1152 - ? + 577 = 1333
(21 X 5) + ? = (480 - 120) Γ· 3
- What will come in the place of question mark (?) in the given expression?
1231 + 1312 + 2113 β 3211 = ? 33 × 5 - ?% of 250 = 62 - 6