Question
40% of ‘s’ along with 60% of ‘t’ makes a total
of 200. If ‘t’ is 70 more than ‘s’, then calculate (2s – t).Solution
ATQ,
Given: 0.4s+0.6t=200 t=s+70 Find: 2s−t Substitute t=s+70 into the first equation: 0.4s+0.6(s+70)=200 0.4s+0.6s+42=200 s+42=200⇒s=158 Find t=s+70=158+70=228 Find 2s−t 2s−t=2⋅158−228=316−228= 88
More Percentage Questions
(560 ÷ 32) × (720 ÷ 48) = ?
∛857375 + ∛91125 = ? + √6889
? = √2704 ÷ (25% of 104) + 73
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(5/8) × 1600 + (2400 ÷ 25) = ?
50 ÷ 2.5 × 64 + ? = 1520
[(√ 529) + 67] x 5 = ?
182 – 517 ÷ 11 - √361 = ?
In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantit...
(3/7) of 700 + 33(1/3)% of 339 - 69 =?
