Question
40% of βsβ along with 60% of βtβ makes a total
of 200. If βtβ is 70 more than βsβ, then calculate (2s β t).Solution
ATQ,
Given: 0.4s+0.6t=200 t=s+70 Find: 2sβt Substitute t=s+70 into the first equation: 0.4s+0.6(s+70)=200 0.4s+0.6s+42=200 s+42=200βs=158 Find t=s+70=158+70=228 Find 2sβt 2sβt=2β 158β228=316β228= 88
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