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    Question

    Total of Series of n terms 1 + 1 + 3 + 1 + 3 + 5 + 1 + 3

    + 5 + 7 ……………………
    A ((n(n+1))/2)^2 Correct Answer Incorrect Answer
    B n² Correct Answer Incorrect Answer
    C (n(n+1)(2n+1))/6 Correct Answer Incorrect Answer
    D none of these Correct Answer Incorrect Answer

    Solution

    Series of n terms is = 1+4+9+16+…………………..+ n² 12+22+32+42+…………………….+ n² = (n(n+1)(2n+1))/6

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