Question
The numbers are in the ratio 7:10:12. If (sum of
smallest and largest) exceeds (sum of smallest and middle) by 30, find the largest number.Solution
ATQ, Let the three numbers be 7x, 10x and 12x respectively. ATQ, (7x + 12x) – (7x + 10x) = 30 Or, 2x = 30 So, x = 15 Therefore, largest number = 12x = 12 × 15 = 180
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