Question
A two-digit number has sum of digits 11. The number
exceeds its reverse by 27. Find the number.Solution
ATQ, Let tens digit = a, ones digit = b a + b = 11 (10a + b) − (10b + a) = 27 => 9(a − b) = 27 => a − b = 3 Solve: a=7, b=4 Answer: 74
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