Question
A two-digit number has sum of digits 11. The number
exceeds its reverse by 27. Find the number.Solution
ATQ, Let tens digit = a, ones digit = b a + b = 11 (10a + b) − (10b + a) = 27 => 9(a − b) = 27 => a − b = 3 Solve: a=7, b=4 Answer: 74
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
...If √b + (1/√b) = 8, then find the value of b + (1/b).
Solve for x:
3x - 4 = 2x + 5
If a = 2 + √3, then the value of (a6 + a4 + a2 + 1)/a3 is
If x : y : z = 5 : 6 : 8, and (3x + 4z) = 188, then find the value of y.
If x2 – 5x + 1 = 0, then find the value of {x2 + (1/x2)}.
- If (u + v) = 11 and uv = 24, then find the value of (u² + v²).
If √z + (1/√z) = 14, then find the value of z + (1/z).
In a best-of-two chess match between Player X and Player Y, the probability that Player X wins a game is (5/9), and the probability that Player Y loses ...
If p = 33 - q - r and pq + r(q + p) = 260, then find the value of (p² + q² + r²).
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