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    Question

    The sum of two numbers is 80 whereas the sum of their

    reciprocals is (22/11). Find the square of the product of the two numbers.
    A 2100 Correct Answer Incorrect Answer
    B 1440 Correct Answer Incorrect Answer
    C 1600 Correct Answer Incorrect Answer
    D 1200 Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the two numbers be 'm' and 'n'.

    So, m + n = 80

    And (1/m) + (1/n) = (22/11)

    Or, {(m + n)/(mn)} = (22/11)

    Or, mn = (11/22) × 80 = 40

    So, required square = 40² = 1600

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