Question
The sum of two numbers is 80 whereas the sum of their
reciprocals is (22/11). Find the square of the product of the two numbers.Solution
ATQ,
Let the two numbers be 'm' and 'n'.
So, m + n = 80
And (1/m) + (1/n) = (22/11)
Or, {(m + n)/(mn)} = (22/11)
Or, mn = (11/22) Ć 80 = 40
So, required square = 40Ā² = 1600
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