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    Question

    Find the least 4-digit number which, when divided by

    16, 20, and 25, leaves a remainder of 7 in each case.
    A 1,007 Correct Answer Incorrect Answer
    B 1,207 Correct Answer Incorrect Answer
    C 1,407 Correct Answer Incorrect Answer
    D 1,607 Correct Answer Incorrect Answer

    Solution

    Prime factorization of 16 = 2тБ┤
    Prime factorization of 20 = 2┬▓ ├Ч 5
    Prime factorization of 25 = 5┬▓ LCM of (16, 20, and 25) = 2тБ┤ ├Ч 5┬▓ = 16 ├Ч 25 = 400 Least 4-digit number divisible by 400 = 1,200 So, required number = 1200 + 7 = 1,207 Hence, option B.

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