Question
Find the least 4-digit number which, when divided by
16, 20, and 25, leaves a remainder of 7 in each case.Solution
Prime factorization of 16 = 2⁴
Prime factorization of 20 = 2² × 5
Prime factorization of 25 = 5² LCM of (16, 20, and 25) = 2⁴ × 5² = 16 × 25 = 400 Least 4-digit number divisible by 400 = 1,200 So, required number = 1200 + 7 = 1,207 Hence, option B.
Find the wrong number in the given number series.
21, 31, 11, 41, 1, 61In each of the following number series, one term is wrong. Find the WRONG term.
6, 9, 15, 27, 53, 99, 195
A-5, A, 35, 52, 78, 115
In each of the following number series, one term is wrong. Find the wrong term.
7, 12, 19, 28, 38, 52
Find the wrong number in the given number series.
32, 61, 92, 129, 170, 211
213, 215, 225, 257, 313, 393
Find the wrong number in the given number series.
2, 6, 12, 22, 30, 42In each of the following number series, one term is wrong. Find the WRONG term.
3, 8, 18, 40, 78, 158
7, 16, 33, 74, 153, 312
Find the wrong number in the given number series.
78, 103, 152, 233, 356, 523
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