Question
If the product of three back-to-back natural numbers is
997920, calculate their total.Solution
ATQ,
Let the three natural numbers be ‘a’, ‘b’, and ‘c’.
ATQ,
a × b × c = 997920
997920 = 98 × 99 × 100
So, the three consecutive natural numbers are 98, 99, and 100
So, the required sum = 98 + 99 + 100 = 297
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Equation 2: 107y² - 504y + 397 = 0
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Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
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I. x
If ‘y1’ and ‘y2’ are the roots of quadratic equation 5y2 – 25y + 15 = 0, then find the quadratic equation whose roots are ‘3y1�...
If 3x – 2y = 10 and xy = 11, the value of 27x³ – 8y³ is __________.
I. 2x² - 15x + 27 = 0
II. 2y² - 13y + 20 = 0
If x^2 - 7x + k = 0 has roots that are equal, what is the value of k?
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Equation 2: y² - 29y + 210 = 0
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II.72y² - 47y - 144 = 0
I. 20y² - 13y + 2 = 0
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