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      Question

      Find the sum of squares of first 6 natural

      numbers.
      A 81 Correct Answer Incorrect Answer
      B 91 Correct Answer Incorrect Answer
      C 95 Correct Answer Incorrect Answer
      D 100 Correct Answer Incorrect Answer

      Solution

      Sum of squares of first 'n' natural numbers = n X (n + 1) X (2n + 1) ÷ 6 Required sum = 6 X (6 + 1) X (2 X 6 + 1) ÷ 6 = 6 X 7 X 13 ÷ 6 = 91

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