Question
'N' is the largest three-digit number that leaves 2 as a
remainder when divided by 9, 12 and 5, Find the sum of digits of 'N'.Solution
LCM of (9, 12 and 5) = 180
Largest 3 digit number that is divisible by 180 = 180 X 5 = 900
So, N = 900 + 2 = 902
So, sum of digits of 'N' = 9 + 0 + 2 = 11
Simplify the following expression and find the final value:
(18 ÷ 6 of 2 + 7 of 5) ÷ 5
(1520 - 1350) ÷ (550 – 500) = ?
Simplify the following expressions and choose the correct option.
[540 ÷ (6 × 3) + 7.5 × 4] ÷ 3 = ?
(64/25)? × (125/512)?-1 = 5/8
52% of 400 + √(?) = 60% of 600 - 25% of 400
What will come in the place of question mark (?) in the given expression?
(72 × 4 – 92) ÷ 14 = ?
32% of 450 + 60% of 150 = ? × 9

82.3 × 644.7 × 723.4 × 815.85 = 72?
961 × 4 ÷ 31 – 15% of 180 = ? – 73