Question
A number is 2/5 more than 33 times its reciprocal. What is
the number?Solution
ATQ,
Let the number be x.
x β 33/x = 2/5
β (xΒ² β 33)/x = 2/5
Cross-multiplying:
5xΒ² β 165 = 2x
β 5xΒ² β 2x β 165 = 0
Factorizing:
5xΒ² β 25x + 23x β 165 = 0
5x(x β 5) + 33(x β 5) = 0
(5x + 33)(x β 5) = 0
So, x = β33/5 or x = 5
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