Question
A = (9/4) × B and C = (1/12) × A. If (A + B + C) =
300, then find the value of (12C – B).Solution
ATQ; A = 12C And, A = (9/4) × B So, 12C = (9/4) × B Or, 16C = 3B Or, B = (16/3)C Since, A + B + C = 300 So, 12C + (16/3)C + C = 300 Or, (36C + 16C + 3C)/3 = 300 Or, 55C = 900 Or, C = 900/55 = 180/11 A = (180/11) × 12 = 2160/11 And, B = (16/3) × (180/11) = 960/11 Required value = 12 × (180/11) – (960/11) = 1200/11
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