Question
Find the sum of squares of first 12 natural
numbers.Solution
Sum of squares of first 'n' natural numbers = n X (n + 1) X (2n + 1) ÷ 6 Required sum = 12 X (12 + 1) X (2 X 12 + 1) ÷ 6 = 12 X 13 X 25 ÷ 6 = 650
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