Question
Sum and difference of two natural numbers is 89 and 15.
Find the square of sum of digits of smaller number.Solution
Let the numbers be 'a' and 'b' (a > b)
So, a + b = 89 --------- (I)
Or, a - b = 15 ---------- (II)
On adding equation I and II,
We get, a + b + a - b = 89 + 15
Or, 2a = 104
Or, 'a' = 52
On putting value of 'a' in equation I,
52 + b = 89
Or, 'b' = 37
Required sum = (3 + 7) 2 Â = 100
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...