Question
Find the sum of all the numbers between 2500 and 9800,
which are divisible by 20, 28 and 35.Solution
LCM of 20, 28 and 35 = 140 So, desired numbers are: 2520, 2660, …, 9660 Number of terms = (9660 – 2520)/140 + 1 = 52 Sum = (52/2) × [2520 + 9660] = 317,640
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_1 m_j_m k_ _m k j 1 m_
Which one set of letters, from the options below, when sequentially placed (left to right) at the gaps in the given letter series, shall complete it: <...
Four letter-clusters have been given, out of which three are alike in some manner and one is different. Select the letter-cluster that is different.
Directions: From the given alternative words, select the word which can be formed using the letters of the given word.Â
PORTFOLIOÂ
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CONTRADICTION
A group of letters is given which are numbered 1 to 8. Four options given below depict combinations of these numbers. Select that combination of numbers...
If in the words, all the letters are arranged in English alphabetical order within the word, how many words will begin with a vowel?
Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?Â
_ Y _ X_ Z X _ Z X _ _ X Y _
If the words are arranged according to the ascending order of the numbers which are attached to them from left to right, then how many alphabets are the...
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