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    Question

    Find the sum of all the numbers between 2500 and 9800,

    which are divisible by 20, 28 and 35.
    A 64000 Correct Answer Incorrect Answer
    B 64800 Correct Answer Incorrect Answer
    C 55800 Correct Answer Incorrect Answer
    D 60800 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    LCM of 20, 28 and 35 = 140 So, desired numbers are: 2520, 2660, тАж, 9660 Number of terms = (9660 тАУ 2520)/140 + 1 = 52 Sum = (52/2) ├Ч [2520 + 9660] = 317,640

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