Question
Find the sum of all the numbers between 2500 and 9800,
which are divisible by 20, 28 and 35.Solution
LCM of 20, 28 and 35 = 140 So, desired numbers are: 2520, 2660, …, 9660 Number of terms = (9660 – 2520)/140 + 1 = 52 Sum = (52/2) × [2520 + 9660] = 317,640
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