Question
Find the sum of all the numbers between 3000 and 14000,
which are divisible by 25, 30 and 40.Solution
LCM of 25, 30 and 40 = 600 So, desired numbers are: 3000, 3600, …, 13800 Number of terms = (13800 – 3000)/600 + 1 = 19 Sum = (19/2) × [3000 + 13800] = 159,900
420Â Â Â Â 342Â Â Â Â Â 272Â Â Â Â Â 212Â Â Â Â Â 156Â Â Â Â 110
...Find the wrong number in the given number series.
5, 10, 20, 40, 85, 1601, 18, 44, 81, 131, 198
216, 432, 144, 288, 96, 191, 64
- Find the wrong number in the given number series.
18, 34, 66, 114, 178, 266 - Find the wrong number in the given number series.
12, 21, 5, 38, 2, 71 Â -2, 0, 8, 32, 64, 66
- Find the wrong number in the given number series.
13, 24, 17, 28, 21, 40 Find the wrong number in the given number series.
1, 8, 27, 65, 125, 21634, 51, 85, 119, 185, 221Â