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      Question

      If 492x51 is a six-digit number that is divisible by 3,

      then find the maximum value of 9x.
      A 63 Correct Answer Incorrect Answer
      B 72 Correct Answer Incorrect Answer
      C 81 Correct Answer Incorrect Answer
      D 90 Correct Answer Incorrect Answer

      Solution

      We know that a number is divisible by 3 only when the sum of its digits is also divisible by 3. So,
      4 + 9 + 2 + x + 5 + 1 = (21 + x) should be divisible by 3 So, possible values of x = 0, 3, 6, 9 Maximum possible value of x = 9 So, required value
      = 9 Γ— 9
      = 81

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