Question
If 492x51 is a six-digit number that is divisible by 3, then find the maximum value of 9x.
Solution
We know that a number is divisible by 3 only when the sum of its digits is also divisible by 3. So,
4 + 9 + 2 + x + 5 + 1 = (21 + x) should be divisible by 3 So, possible values of x = 0, 3, 6, 9 Maximum possible value of x = 9 So, required value
= 9 × 9
= 81
More No. System Questions
- There are 120 candies, 120 chocolates, and 200 sweets to be distributed among groups A, B, and C, where each student in group A receives 5 candies, each st...
- Which of the following pairs is NOT coprime?
- What should be subtracted from 64 and 40 to make the ratio of resulting numbers 3:1?
- Three numbers are in the ratio 5:9:12. The sum of the largest and smallest of these numbers is 8500. What is the difference between the largest and smalles...
- Find the value of 'a' in the given data if the mean of the given data is 27. 20, 25, 30, 28, 26, 24, a, 29, 22, 23
- For two numbers, the square of their sum is 1024 and the sum of their squares is 640. What is the product of the numbers?
- Choose the number which is different from the group.
- a, b and c are three integers. The sum of a and b is 61. If b is divided by a then the quotient is 2 and the remainder is 7. If cn - 2 is largest negative ...
- Ten numbers are arranged in decreasing order. The average of the first nine numbers is 55, and the average of the last nine numbers is 50. What is the diff...
- A two-digit natural number has the property that the digit in the tens place is the square of the digit in the units place. When the original number is add...
Relevant for Exams:
