Question
If 492x51 is a six-digit number that is divisible by 3,
then find the maximum value of 9x.Solution
We know that a number is divisible by 3 only when the sum of its digits is also divisible by 3. So,
4 + 9 + 2 + x + 5 + 1 = (21 + x) should be divisible by 3 So, possible values of x = 0, 3, 6, 9 Maximum possible value of x = 9 So, required value
= 9 × 9
= 81
CO2emitters are used in active packaging of
a)Â Â Â Vegetables and fruits
b)Â Â Â Fish
c)Â Â Â Meat
d)Â Â Â Poultry
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a)Â Â Â Saturated fatty acids have single bond between C-C.
b)Â Â Â Unsaturated fatty...
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