Question
If 248x73 is a six-digit number that is divisible by 3,
then find the maximum value of 4x.Solution
We know that a number is divisible by 3 only when the sum of its digits is also divisible by 3. So,
2 + 4 + 8 + x + 7 + 3 = (24 + x) should be divisible by 3 So, possible values of x = 0, 3, 6, 9 Maximum possible value of x = 9 So, required value
= 4 × 9
= 36
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