Question
If 864x12 is a six-digit number that is divisible by 3, then find the maximum value of 8x.
Solution
We know that a number is divisible by 3 only when the sum of its digits is also divisible by 3. So,
8 + 6 + 4 + x + 1 + 2 = (21 + x) should be divisible by 3 So, possible values of x = 0, 3, 6, 9 Maximum possible value of x = 9 So, required value
= 8 × 9
= 72
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