Question
Three numbers are in the ratio 6:9:13. The difference of
the sums (first + third) and (first + second) is 52. Find the largest number.Solution
ATQ, Let the three numbers be 6x, 9x and 13x respectively. ATQ, (6x + 13x) – (6x + 9x) = 52 Or, 4x = 52 So, x = 13 Therefore, largest number = 13x = 13 × 13 = 169
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