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    Question

    There are nine consecutive even numbers such that the

    smallest number is 50% of the largest number. Find the sum of the second lowest and second highest numbers.
    A 44 Correct Answer Incorrect Answer
    B 40 Correct Answer Incorrect Answer
    C 48 Correct Answer Incorrect Answer
    D 54 Correct Answer Incorrect Answer

    Solution

    ATQ, Let the consecutive even numbers be: x, x + 2, x + 4, x + 6, x + 8, x + 10, x + 12, x + 14, x + 16 According to question: x = 0.50 × (x + 16) x = 0.5x + 8 0.5x = 8 x = 16 So the desired sum = (x + 2) + (x + 14) = 16 + 2 + 16 + 14 = 48

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