Question
There are nine consecutive even numbers such that the
smallest number is 50% of the largest number. Find the sum of the second lowest and second highest numbers.Solution
ATQ, Let the consecutive even numbers be: x, x + 2, x + 4, x + 6, x + 8, x + 10, x + 12, x + 14, x + 16 According to question: x = 0.50 Ć (x + 16) x = 0.5x + 8 0.5x = 8 x = 16 So the desired sum = (x + 2) + (x + 14) = 16 + 2 + 16 + 14 = 48
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