Question
How many 4-digit numbers can be formed from digits 1β9
(no repetition) such that the number is divisible by 3?Solution
Sum of digits of number must be multiple of 3. Total 4-digit numbers (without repetition) = 9Γ8Γ7Γ6 = 3024. β of them will have digit-sum divisible by 3 (uniform distribution). Answer: 3024 / 3 = 1008
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