Question
Find the smallest number which when divided by 5, 6 and
8 leaves a remainder 3 in each case.Solution
ATQ, Let the number be N. When divided by 5, 6 and 8, remainder is 3. So N - 3 is divisible by 5, 6 and 8. N - 3 = LCM(5, 6, 8) 5 = 5 6 = 2 * 3 8 = 23 LCM = 23 * 3 * 5 = 8 * 3 * 5 = 120 So N - 3 = 120 N = 120 + 3 = 123 Answer: 123
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