Question
Find the sum of 1² + 3² + 5² +
7²……………………………….23².Solution
N = 23(last term) Sum of square of consecutive odd numbers = (n(n+1)(n+2))/6 ,where N= last term ⇒ (23(23+1)(23+2))/6 ⇒ (23 ×24 ×25)/6 ⇒ 2300
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WOSUPA
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