Question
Find the sum of 1² + 3² + 5² +
7²……………………………….23².Solution
N = 23(last term) Sum of square of consecutive odd numbers = (n(n+1)(n+2))/6  ,where N= last term ⇒  (23(23+1)(23+2))/6 ⇒  (23 ×24 ×25)/6 ⇒  2300
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X: 16, 54, 35, 25, 44, 51
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