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    Question

    Find the total sum of all numbers between 60 and 320

    that are divisible by both 12 and 18.
    A 960 Correct Answer Incorrect Answer
    B 1260 Correct Answer Incorrect Answer
    C 1080 Correct Answer Incorrect Answer
    D 1568 Correct Answer Incorrect Answer

    Solution

    Numbers which are divisible by 12 as well as 18, must be divisible by 36.
    So, numbers between 60 and 320 which are divisible by 36 are: 72, 108, 144, ........., 288
    So, total number of terms between 60 and 320 which are divisible by 36 = (288 – 72)/36 + 1 = 6 + 1 = 7
    Desired sum = (7/2) × {72 + 288} = 7 × 180 = 1260

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