Question
Find the total sum of all numbers between 60 and 320
that are divisible by both 12 and 18.Solution
Numbers which are divisible by 12 as well as 18, must be divisible by 36.
So, numbers between 60 and 320 which are divisible by 36 are: 72, 108, 144, ........., 288
So, total number of terms between 60 and 320 which are divisible by 36 = (288 – 72)/36 + 1 = 6 + 1 = 7
Desired sum = (7/2) × {72 + 288} = 7 × 180 = 1260
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