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      Question

      Find the total sum of all numbers between 60 and 320

      that are divisible by both 12 and 18.
      A 960 Correct Answer Incorrect Answer
      B 1260 Correct Answer Incorrect Answer
      C 1080 Correct Answer Incorrect Answer
      D 1568 Correct Answer Incorrect Answer

      Solution

      Numbers which are divisible by 12 as well as 18, must be divisible by 36.
      So, numbers between 60 and 320 which are divisible by 36 are: 72, 108, 144, ........., 288
      So, total number of terms between 60 and 320 which are divisible by 36 = (288 – 72)/36 + 1 = 6 + 1 = 7
      Desired sum = (7/2) Γ— {72 + 288} = 7 Γ— 180 = 1260

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