Question
If (2/3)rd of ‘x’ exceeds
(2/5)th of (x + 5) by 6, then find the value of ‘x’.Solution
ATQ; {(2/5) × (x + 5)} + 6 = (2/3) × x Or, 2x + 10 + 30 = (10/3) × x Or, 40 = (10x/3 – 2x) Or, 40 = (4x/3) So, x = 30
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