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The value of ‘q’ is one less than the value of ‘s’.
q = (s-1) Eq.(i)
The average of ‘p’ and ‘s’ is 4.
p+s = 4x2 = 8 Eq.(ii)
The value of ‘r’ is 3 less than the value of ‘s’.
r = (s-3) Eq.(iii)
If the value of ‘r’ is the smallest prime number.
So r = 2 .
Put the value of ‘r’ in Eq.(iii).
2 = (s-3)
s = 3+2
s = 5
Put the value of ‘s’ Eq.(ii).
p+5 = 8
p = 8-5
p = 3
Put the value of ‘s’ Eq.(i).
q = (5-1)
q = 4
The sum of (p/q)+(q/r)+(r/s)+(s/t) = (239/60).
Put the value of ‘p‘, ‘q‘, ‘r‘ and ‘s‘ in the above equation.
(3/4)+(4/2)+(2/5)+(5/t) = (239/60)
(63/20)+(5/t) = (239/60)
(5/t) = (239/60)-(63/20)
(5/t) = (239-189)/60
(5/t) = (50/60)
t = 6
Value of (p+q+s+t)/4 = (3+4+5+6)/4
= 18/4
= 4.5
Statement:
O ≤ P > K ≤ L; W ≤ X = K > R; Q > L
Conclusion:
I. O > K
II. L < P
Statements: I < P = S ≥ O > W < E≤ G ≥ A
Conclusion
I: O ≤ P
II: G > O
Study the following information carefully and answer the questions given below:
Statements:
R ≤ O < N, X = I, R ≥ M = I
Statements: B < C ≤ D; A < B; E < D ≥ F
Conclusions:
I. F < B
II. A < D
III. E < C
Statements: M % N, N & A, A @ B, B # C
Conclusions: I. C & A II. M # B
...Which of the following does not make J @ K and R # K definitely not true?
Statements: I < Q = S = T ≤ U ≤ W < X > Y = V
Conclusions:
I. I > Y
II. W ≥ Q
III. T < V
...Statements: Q < R = S ≥ T = U; S < V; S = X
Conclusion: I. X ≥ U II. V < Q
If we arrange all the letters of the word ‘SUPPLIERS’ in alphabetical order from the left end, then, which letter will remain at its initial positio...
Statements: T > S > R, L ≥ D < R, L ≤ O ≤ Z
Conclusions:
I. T > L
II. S > D
III. Z ≥ R
...