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The value of ‘q’ is one less than the value of ‘s’.
q = (s-1) Eq.(i)
The average of ‘p’ and ‘s’ is 4.
p+s = 4x2 = 8 Eq.(ii)
The value of ‘r’ is 3 less than the value of ‘s’.
r = (s-3) Eq.(iii)
If the value of ‘r’ is the smallest prime number.
So r = 2 .
Put the value of ‘r’ in Eq.(iii).
2 = (s-3)
s = 3+2
s = 5
Put the value of ‘s’ Eq.(ii).
p+5 = 8
p = 8-5
p = 3
Put the value of ‘s’ Eq.(i).
q = (5-1)
q = 4
The sum of (p/q)+(q/r)+(r/s)+(s/t) = (239/60).
Put the value of ‘p‘, ‘q‘, ‘r‘ and ‘s‘ in the above equation.
(3/4)+(4/2)+(2/5)+(5/t) = (239/60)
(63/20)+(5/t) = (239/60)
(5/t) = (239/60)-(63/20)
(5/t) = (239-189)/60
(5/t) = (50/60)
t = 6
Value of (p+q+s+t)/4 = (3+4+5+6)/4
= 18/4
= 4.5
2/5 of 3/4 of 7/9 of 7200 = ?
16 × ? + 36% of 250 = 410
808 ÷ (128)1/7 + 482 = 4 × ? + 846
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
`(21 xx 51 + 54)/(9 xx 14 - 30 )` =?
12.232 + 29.98% of 539.99 = ? × 5.99
? = 120% of (652 ÷ 132 ) + 33 × 8
√? + √1296 + √729 = 464/4
The value of ((0.27)2-(0.13)2) / (0.27 + 0.13) is:
I. x² + 3x – 154 = 0
II. y² + 5y – 126 = 0