Question
A six-digit number 4c68d2 is divisible by 12. Find the
sum of all possible values of 'c' for the largest possible value of 'd'.Solution
ATQ, A number is divisible by 12 when it is divisible by 3 and 4 both. A number is divisible by 4 when its last two digits are divisible by 4. Here 'd2' is divisible by 4 for 'd' = 0, 2, 4, 6, and 8. Largest possible value of 'd' = 8. A number is divisible by 3 when the sum of its digits is divisible by 3. Sum of digits of 4c6882 = 4 + c + 6 + 8 + 8 + 2 = 28 + c. So, possible values of 'c' = 2, 5, and 8. Therefore, the required sum = 2 + 5 + 8 = 15.
What is the maximum number of self-regulatory organizations (SROs) that RBI will approve for the NBFC sector?
Under the FEMA norms issued by RBI for direct listing on international exchanges, where must the proceeds from the sale of equity shares be remitted or ...
What is the purpose of the Reserve Bank of India (RBI) introducing a Fully Accessible Route (FAR) for investments in sovereign green bonds?
What is India’s rank in Global Hunger Index (GHI) 2021 which is released by Concern Worldwide and German organisation Welt Hunger Hilfe?
Which Indian city tops the list of 10 ranked for the best high streets, as per the Knight Frank report?
What is the projected government debt-to-GDP ratio for India by 2030, as per the same outlook?
What is the purpose of the Mekedatu reservoir project in Karnataka?
The term “FLOPs” is often heard in the news. It corresponds to:
How many entrepreneurs has GAME supported since its inception in 2018?
NLC India Limited has recently won a 810 MW Solar PV project capacity from which state's power utility?
