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      Question

      In a group of three numbers first is double of second

      and half of third. The average of three numbers is 56. Find the difference between the first number and third number?
      A 34 Correct Answer Incorrect Answer
      B 48 Correct Answer Incorrect Answer
      C 26 Correct Answer Incorrect Answer
      D 38 Correct Answer Incorrect Answer
      E 42 Correct Answer Incorrect Answer

      Solution

      Let the first number be β€˜x’ Second number = x/2 Third number = 2x According to the question, (x+x/2+2x)/3 = 56 (2x+x+4x)/6 = 56 7x =56 Γ— 6 x = 48 ∴ Required difference = 96 - 48 = 48

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